Question
                Find the area of the trapezoid with the following measurements:base 1: 4ft base 2: 10ft height:8ft
A.32ft²
B.80ft²
C.56ft²
D.320ft²
Best answer
            
            
        A.32ft²
B.80ft²
C.56ft²
D.320ft²
Best answer
Answers
                                                    There are no human answers yet.
                                            
                
                    Answered by
            GPT-4o mini
            
    To find the area of a trapezoid, you can use the formula:
\[
\text{Area} = \frac{(b_1 + b_2)}{2} \times h
\]
where \( b_1 \) and \( b_2 \) are the lengths of the two bases, and \( h \) is the height.
In your case:
- \( b_1 = 4 \, \text{ft} \)
- \( b_2 = 10 \, \text{ft} \)
- \( h = 8 \, \text{ft} \)
Now, plug in the values:
\[
\text{Area} = \frac{(4 + 10)}{2} \times 8
\]
Calculating the sum of the bases:
\[
(4 + 10) = 14
\]
Then, divide by 2:
\[
\frac{14}{2} = 7
\]
Now multiply by the height:
\[
\text{Area} = 7 \times 8 = 56 \, \text{ft}²
\]
So, the area of the trapezoid is \( 56 \, \text{ft}² \).
The correct answer is **C. 56ft²**.
    
\[
\text{Area} = \frac{(b_1 + b_2)}{2} \times h
\]
where \( b_1 \) and \( b_2 \) are the lengths of the two bases, and \( h \) is the height.
In your case:
- \( b_1 = 4 \, \text{ft} \)
- \( b_2 = 10 \, \text{ft} \)
- \( h = 8 \, \text{ft} \)
Now, plug in the values:
\[
\text{Area} = \frac{(4 + 10)}{2} \times 8
\]
Calculating the sum of the bases:
\[
(4 + 10) = 14
\]
Then, divide by 2:
\[
\frac{14}{2} = 7
\]
Now multiply by the height:
\[
\text{Area} = 7 \times 8 = 56 \, \text{ft}²
\]
So, the area of the trapezoid is \( 56 \, \text{ft}² \).
The correct answer is **C. 56ft²**.
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