Given f(x)=4x2−10x−3 , according to the Remainder Theorem, f(2) can be found by finding the remainder of which of the following division quotients?(1 point) Responses (4x2−10x−3)÷(x−2) left parenthesis 4 x squared minus 10 x minus 3 right parenthesis divided by left parenthesis x minus 2 right parenthesis (4x2−10x−3)÷(x+2) left parenthesis 4 x squared minus 10 x minus 3 right parenthesis divided by left parenthesis x plus 2 right parenthesis (4x2−10x−3)÷2 left parenthesis 4 x squared minus 10 x minus 3 right parenthesis divided by 2 (4x2−10x−3)÷x left parenthesis 4 x squared minus 10 x minus 3 right parenthesis divided by x
1 answer
According to the Remainder Theorem, the value of a polynomial \( f(x) \) at a given \( x = a \) can be found by evaluating the remainder of the polynomial when divided by \( (x - a) \).
In this case, we want to find \( f(2) \). Therefore, we need to divide the polynomial \( f(x) = 4x^2 - 10x - 3 \) by \( (x - 2) \).
So the correct answer is: \[ (4x^2 - 10x - 3) \div (x - 2) \]
