Asked by meoww :3
Create an equivalent expression for 11−7 • 115.
Group of answer choices
one over eleven raised to the second power
one over eleven raised to the power of negative two
112
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To simplify the expression \( 11 - 7 \cdot 115 \), we first perform the multiplication:
\[
7 \cdot 115 = 805
\]
Next, we subtract this from 11:
\[
11 - 805 = -794
\]
Now, we need to determine which of the answer choices corresponds to \(-794\).
1. **One over eleven raised to the second power:**
This is \(\frac{1}{11^2} = \frac{1}{121}\).
2. **One over eleven raised to the power of negative two:**
This is \(\frac{1}{11^{-2}} = 11^2 = 121\).
3. **112:**
This is simply 112.
None of the given choices correspond to \(-794\).
If we look at the options, the correct choice based on mathematical interpretation would lean towards **"one over eleven raised to the power of negative two,"** but it doesn’t relate to the initial calculation of \(11 - 7 \cdot 115\).
In summary, while none of these choices accurately represent the value we calculated, \(\frac{1}{11^{-2}} = 121\) is the closest interpretation typically; however, it does not equal the original calculation.
\[
7 \cdot 115 = 805
\]
Next, we subtract this from 11:
\[
11 - 805 = -794
\]
Now, we need to determine which of the answer choices corresponds to \(-794\).
1. **One over eleven raised to the second power:**
This is \(\frac{1}{11^2} = \frac{1}{121}\).
2. **One over eleven raised to the power of negative two:**
This is \(\frac{1}{11^{-2}} = 11^2 = 121\).
3. **112:**
This is simply 112.
None of the given choices correspond to \(-794\).
If we look at the options, the correct choice based on mathematical interpretation would lean towards **"one over eleven raised to the power of negative two,"** but it doesn’t relate to the initial calculation of \(11 - 7 \cdot 115\).
In summary, while none of these choices accurately represent the value we calculated, \(\frac{1}{11^{-2}} = 121\) is the closest interpretation typically; however, it does not equal the original calculation.
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