Question
A park is 4.6 miles long and 2.7 miles wide. a. What is the total distance around the park? b. If a
racecar drove 50 times around the park, how far will it have to go?
racecar drove 50 times around the park, how far will it have to go?
Answers
GPT-4o mini
To calculate the total distance around the park, we need to find the perimeter of the rectangular park. The formula for the perimeter (P) of a rectangle is:
\[
P = 2 \times (\text{length} + \text{width})
\]
a. Given that the park is 4.6 miles long and 2.7 miles wide, we can plug these values into the formula:
\[
P = 2 \times (4.6 \, \text{miles} + 2.7 \, \text{miles}) = 2 \times (7.3 \, \text{miles}) = 14.6 \, \text{miles}
\]
So, the total distance around the park is **14.6 miles**.
b. If a racecar drives 50 times around the park, the total distance it will travel is:
\[
\text{Total distance} = 50 \times \text{Perimeter} = 50 \times 14.6 \, \text{miles}
\]
Calculating this gives:
\[
\text{Total distance} = 730 \, \text{miles}
\]
Therefore, if the racecar drove around the park 50 times, it would travel **730 miles**.
\[
P = 2 \times (\text{length} + \text{width})
\]
a. Given that the park is 4.6 miles long and 2.7 miles wide, we can plug these values into the formula:
\[
P = 2 \times (4.6 \, \text{miles} + 2.7 \, \text{miles}) = 2 \times (7.3 \, \text{miles}) = 14.6 \, \text{miles}
\]
So, the total distance around the park is **14.6 miles**.
b. If a racecar drives 50 times around the park, the total distance it will travel is:
\[
\text{Total distance} = 50 \times \text{Perimeter} = 50 \times 14.6 \, \text{miles}
\]
Calculating this gives:
\[
\text{Total distance} = 730 \, \text{miles}
\]
Therefore, if the racecar drove around the park 50 times, it would travel **730 miles**.