Question

What is the date today if July 7 was six days before one day after 4 days before the day before the day before 8 days after the day before yesterday

Answer 1

Let's break down the statement step by step to determine the date.

1. **"the day before yesterday"**: Let's call today \( T \). The day before yesterday would be \( T - 2 \).

2. **"8 days after the day before yesterday"**: This would be \( (T - 2) + 8 = T + 6 \).

3. **"the day before" that**: This means we go one day back from \( T + 6 \), which is \( (T + 6) - 1 = T + 5 \).

4. **"4 days before" that**: Now we subtract 4 days from \( T + 5 \), which yields \( (T + 5) - 4 = T + 1 \).

5. **"one day after" that**: Next, we add one day, resulting in \( (T + 1) + 1 = T + 2 \).

6. **"six days before" that**: Finally, we subtract 6 days from \( T + 2 \), giving us \( (T + 2) - 6 = T - 4 \).

So the original statement boils down to saying that July 7 was \( T - 4 \). This means:

\[
T - 4 = \text{July 7}
\]

To find \( T \), we can express this as:

\[
T = \text{July 7} + 4 \text{ days}
\]

Calculating \( T \):

- July 8 (1 day after July 7)
- July 9 (2 days after July 7)
- July 10 (3 days after July 7)
- **July 11 (4 days after July 7)**

Thus, today is **July 11**.