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To determine the force with which the softball will hit the catcher's mitt, we can use Newton's second law of motion, which states:
\[ F = m \cdot a \]
where:
- \( F \) is the force,
- \( m \) is the mass,
- \( a \) is the acceleration.
Given:
- The mass \( m = 0.2 \) kg,
- The acceleration \( a = 8 \) m/s².
Substituting the values into the equation:
\[ F = 0.2 \, \text{kg} \cdot 8 \, \text{m/s}^2 = 1.6 \, \text{N} \]
Therefore, the force with which the ball will hit the catcher's mitt is **1.6 N**.