A 0.2-kilogram softball is thrown torward a catcher's mitt. The ball is accelerating at a rate of 8 meters per second squared. With what force will the ball hit the catcher's mitt? 40 N. 7.9 N. 8.2 N. 1.6 N.

To determine the force with which the softball will hit the catcher's mitt, we can use Newton's second law of motion, which states:

\[ F = m \cdot a \]

where:
- \( F \) is the force,
- \( m \) is the mass,
- \( a \) is the acceleration.

Given:
- The mass \( m = 0.2 \) kg,
- The acceleration \( a = 8 \) m/s².

Substituting the values into the equation:

\[ F = 0.2 \, \text{kg} \cdot 8 \, \text{m/s}^2 = 1.6 \, \text{N} \]

Therefore, the force with which the ball will hit the catcher's mitt is **1.6 N**.