325-48

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To solve the subtraction problem \( 325 - 48 \), we can break it down into simpler steps:

  1. Align the numbers:

      325
    -  48
    
  2. Subtract the numbers starting from the rightmost column (the units):

    • In the units place, we have \( 5 - 8 \). Since \( 5 \) is smaller than \( 8 \), we need to borrow \( 1 \) from the tens column.
    • This makes the \( 2 \) in the tens place a \( 1 \), and the \( 5 \) becomes \( 15 \) (since we borrowed 10).

    Now, calculate:

    • \( 15 - 8 = 7 \)
  3. Move to the tens column:

    • Now we need to subtract \( 1 \) (after borrowing) from \( 2 \), so:
    • \( 1 - 4 \). Again, \( 1 \) is smaller than \( 4 \), so we need to borrow again from the hundreds column.
    • Borrowing \( 1 \) from \( 3 \) (making it \( 2 \)), turns the \( 1 \) into \( 11 \).

    Now, calculate:

    • \( 11 - 4 = 7 \)
  4. Move to the hundreds column:

    • Now we just have:
    • \( 2 - 0 = 2 \)
  5. Putting it all together:

    • From the hundreds column, we have \( 2 \),
    • From the tens column, we have \( 7 \),
    • From the units column, we have \( 7 \).

So, putting everything together, we get:

\[ 325 - 48 = 277 \]

Thus, the final answer is \( 277 \).