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Use the periodic table to answer the question.

An illustration shows the periodic table of elements. The elements in the periodic table are arranged in groups (columns numbered 1 through 18) and periods (rows numbered 1 through 7) such that the atomic number increases along a period from left to right. The elements are divided into the following categories: · Alkali metals · Alkaline earth metals · Transition metals · Post-transition metals · Lanthanides · Actinides · Metalloids · Nonmetals · Noble gases · Unknown The elements are also classified on the basis of their physical states as follows: · Solid · Liquid · Gas · Unknown The element sulfur is enlarged with the following properties. · Chemical symbol: S · Name: Sulfur · Atomic Number: 16 · Atomic mass: 32.06 · Common oxidation states: 6, 4, 2, negative 2 · Electronegativity: 2.58 · Ionization energies: 999.589 · Electron configuration: [Ne] 3s2 3p4

Which statement correctly compares the valence electrons for atoms of francium (Fr) and barium (Ba)?

(1 point)
Responses

Barium has more valence electrons, and they are in a higher energy level.
Barium has more valence electrons, and they are in a higher energy level.

Francium has fewer valence electrons, but they are in a higher energy level.
Francium has fewer valence electrons, but they are in a higher energy level.

Barium has fewer valence electrons, but they are in a higher energy level.
Barium has fewer valence electrons, but they are in a higher energy level.

Francium has more valence electrons, and they are in a higher energy level.

1 answer

To answer the question correctly, we need to first look at the electronic configuration and the position of both francium (Fr) and barium (Ba) in the periodic table.

  • Francium (Fr) is in Group 1 (alkali metals) and its atomic number is 87. It has 1 valence electron in the outermost energy level, which is the 7th level (n=7).

  • Barium (Ba) is in Group 2 (alkaline earth metals) and its atomic number is 56. It has 2 valence electrons in the outermost energy level, which is the 6th level (n=6).

Now let's compare their valence electrons:

  • Francium has 1 valence electron and it is located in the 7th energy level.
  • Barium has 2 valence electrons and they are in the 6th energy level.

Given this information, the correct comparison is:

Francium has fewer valence electrons, but they are in a higher energy level.

So, the correct answer is:

Francium has fewer valence electrons, but they are in a higher energy level.