To find the acceleration of the object in both scenarios, we can use Newton's second law of motion, which states that \( F_{net} = m \cdot a \), where \( F_{net} \) is the net force, \( m \) is the mass, and \( a \) is the acceleration.
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Initial scenario:
- Net force \( F_{net} = 0.8 , \text{N} \)
- Mass \( m = 1.5 , \text{kg} \)
We can rearrange the equation to solve for acceleration: \[ a = \frac{F_{net}}{m} = \frac{0.8 , \text{N}}{1.5 , \text{kg}} \approx 0.5333 , \text{m/s}^2. \]
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New scenario:
- Net force \( F_{net} = 0.2 , \text{N} \)
Again, calculate the acceleration: \[ a = \frac{F_{net}}{m} = \frac{0.2 , \text{N}}{1.5 , \text{kg}} \approx 0.1333 , \text{m/s}^2. \]
Now, let's compare the two accelerations:
- Initial acceleration \( a_1 \approx 0.5333 , \text{m/s}^2 \)
- New acceleration \( a_2 \approx 0.1333 , \text{m/s}^2 \)
Notice that the new acceleration \( \approx 0.1333 , \text{m/s}^2 \) is indeed \( \frac{1}{4} \) of the original acceleration \( \approx 0.5333 , \text{m/s}^2 \).
Therefore, the correct response is: The acceleration decreases to a quarter of its original value, or about 0.13 m/s².
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