In a closed system consisting of a cannon and a cannonball, the kinetic energy of a cannon is 72,000 J.

If the cannonball is 18 kg and has a velocity of 23 m/s when fired from the cannon, what is the total
kinetic energy of the system? (1 point)

67,239 J

76,761 J

71,793 J

72,207 J

1 answer

To find the total kinetic energy of the system (cannon + cannonball), we need to calculate the kinetic energy of the cannonball and then add it to the kinetic energy of the cannon.

The formula for kinetic energy (KE) is given by:

\[ KE = \frac{1}{2} mv^2 \]

where \( m \) is the mass and \( v \) is the velocity.

  1. Calculate the kinetic energy of the cannonball:
    • Mass of the cannonball \( m = 18 , \text{kg} \)
    • Velocity of the cannonball \( v = 23 , \text{m/s} \)

\[ KE_{\text{cannonball}} = \frac{1}{2} \times 18 , \text{kg} \times (23 , \text{m/s})^2 \]

\[ KE_{\text{cannonball}} = \frac{1}{2} \times 18 \times 529 \]

\[ KE_{\text{cannonball}} = 9 \times 529 = 4761 , \text{J} \]

  1. Now, add the kinetic energy of the cannonball to the kinetic energy of the cannon to get the total kinetic energy of the system:

\[ KE_{\text{total}} = KE_{\text{cannon}} + KE_{\text{cannonball}} \]

Given that \( KE_{\text{cannon}} = 72,000 , \text{J} \):

\[ KE_{\text{total}} = 72,000 , \text{J} + 4,761 , \text{J} = 76,761 , \text{J} \]

Therefore, the total kinetic energy of the system is 76,761 J.