Use the table to answer the question.

Minutes 1 8 15
Math Problems x 48 y
Jesse can complete 48 math problems in 8 minutes. How many math problems can she complete in 1 minute? How many math problems can she complete in 15 minutes?

(1 point)
Responses

9; 23
9; 23

7; 22
7; 22

6; 90
6; 90

24; 72
24; 72
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Answers

Use the table to answer the question.

White Blue
3 4
x 8
9 12
12 y
For every 4 blue crayons in a box, there are 3 white ones. How many white crayons are there if there are 8 blue ones? How many blue crayons are there if there are 12 white ones?

(1 point)
Responses

9; 12
9; 12

4; 8
4; 8

12; 16
12; 16

6; 16
6; 16
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page 8 of 8
Use the table to answer the question.

8 48
10 60
x 72
y 84Analyze the ratios in the table to find the missing values.(1 point)
Responses

18; 26
18; 26

432; 504
432; 504

12; 14
12; 14

22; 34
Thanks!!
Answered by GPT-4o mini
To determine how many math problems Jesse can complete in 1 minute and 15 minutes, we can use the information given.

Jesse completes 48 math problems in 8 minutes.

First, we calculate how many problems she completes in 1 minute:

\[
\text{Problems per minute} = \frac{48 \text{ problems}}{8 \text{ minutes}} = 6 \text{ problems per minute}
\]

Now, to find out how many problems she can complete in 15 minutes, we multiply the problems completed per minute by the number of minutes:

\[
\text{Problems in 15 minutes} = 6 \text{ problems per minute} \times 15 \text{ minutes} = 90 \text{ problems}
\]

So, Jesse can complete 6 math problems in 1 minute and 90 math problems in 15 minutes. The correct answer is:

**6; 90**
Answered by GPT-4o mini
The problem states that for every 4 blue crayons, there are 3 white crayons. We can set up a ratio based on that information:

\[
\text{White : Blue} = 3 : 4
\]

**1. Finding the number of white crayons when there are 8 blue crayons:**

We know that if there are 4 blue crayons, there are 3 white crayons. To find out how many white crayons correspond to 8 blue crayons, we can set up the proportions:

\[
\frac{3 \text{ white}}{4 \text{ blue}} = \frac{x \text{ white}}{8 \text{ blue}}
\]

Cross-multiplying gives:

\[
3 \times 8 = 4 \times x
\]
\[
24 = 4x
\]
\[
x = 6
\]

So, when there are 8 blue crayons, there are **6 white crayons**.

**2. Finding the number of blue crayons when there are 12 white crayons:**

Again using the ratio:

\[
\frac{3 \text{ white}}{4 \text{ blue}} = \frac{12 \text{ white}}{y \text{ blue}}
\]

Cross-multiplying gives:

\[
3y = 4 \times 12
\]
\[
3y = 48
\]
\[
y = 16
\]

So, when there are 12 white crayons, there are **16 blue crayons**.

The answers are: **6; 16**.

None of the provided responses exactly match this pair. Please verify if there might be additional context or an alternate interpretation of the ratios involved.
Answered by GPT-4o mini
To analyze the ratios in the table, let's first identify the pattern in the provided values.

The table looks like this:

| First Value | Second Value |
|------------------|------------------|
| 8 | 48 |
| 10 | 60 |
| x | 72 |
| y | 84 |

### Finding the ratio:

1. **Calculate the ratio of the first and second values in the first two rows:**

- For the first row:
\[
\frac{48}{8} = 6
\]

- For the second row:
\[
\frac{60}{10} = 6
\]

The ratio appears to be consistent at \( \frac{\text{Second Value}}{\text{First Value}} = 6 \).

### Finding \( x \) when the second value is 72:

We use the same ratio to find \( x \):
\[
\frac{72}{x} = 6
\]

Cross-multiply to solve for \( x \):
\[
72 = 6x
\]
\[
x = \frac{72}{6} = 12
\]

### Finding \( y \) when the second value is 84:

Now, we can find \( y \) using the same ratio:
\[
\frac{84}{y} = 6
\]

Again, cross-multiply to solve for \( y \):
\[
84 = 6y
\]
\[
y = \frac{84}{6} = 14
\]

### Conclusion:
Thus, the missing values are \( x = 12 \) and \( y = 14 \).

The correct response is **12; 14**.
Answered by GPT-4o mini
You're welcome! If you have any more questions or need further assistance, feel free to ask. Happy studying!
Answered by GPT-4o mini
😊 I'm glad to see you're happy! If there's anything else on your mind or anything you'd like to discuss, just let me know!

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