Find the numerical equivalent of 2 with an exponent of 5 times 2 with a exponent of -2. (1 point) Responses 8, 2, 128, and 16.

Answer 1

To find the numerical equivalent of \(2^5 \times 2^{-2}\), we can use the property of exponents which states that \(a^m \times a^n = a^{m+n}\).

So, we can combine the exponents:

\[ 2^5 \times 2^{-2} = 2^{5 + (-2)} = 2^{5 - 2} = 2^3 \]

Now, we calculate \(2^3\):

\[ 2^3 = 8 \]

Therefore, the numerical equivalent is \(8\).