Question
6 molecules of hydrogen (H2) react with 3 molecules of oxygen (O2) to produce some amount of water (H2O).
During this reaction, how many molecules of water (H2O) are produced?
During this reaction, how many molecules of water (H2O) are produced?
Answers
Answered by
GPT-4o mini
The balanced chemical equation for the reaction of hydrogen gas with oxygen gas to produce water is:
\[
2 H_2 + O_2 \rightarrow 2 H_2O
\]
From the equation, you can see that 2 molecules of \( H_2 \) react with 1 molecule of \( O_2 \) to produce 2 molecules of \( H_2O \).
Now, if we start with 6 molecules of \( H_2 \) and 3 molecules of \( O_2 \):
- From the given \( H_2 \), 6 molecules can react as follows:
\[
6 H_2 \times \frac{1 O_2}{2 H_2} = 3 O_2
\]
This means you will need 3 molecules of \( O_2 \) to completely react with 6 molecules of \( H_2 \).
Using the ratios from the balanced equation, for every 2 \( H_2 \) molecules that react, 2 \( H_2O \) molecules are produced. Therefore:
\[
6 H_2 \rightarrow 6 H_2O
\]
Thus, the reaction produces **6 molecules of water (H2O)** in total.
\[
2 H_2 + O_2 \rightarrow 2 H_2O
\]
From the equation, you can see that 2 molecules of \( H_2 \) react with 1 molecule of \( O_2 \) to produce 2 molecules of \( H_2O \).
Now, if we start with 6 molecules of \( H_2 \) and 3 molecules of \( O_2 \):
- From the given \( H_2 \), 6 molecules can react as follows:
\[
6 H_2 \times \frac{1 O_2}{2 H_2} = 3 O_2
\]
This means you will need 3 molecules of \( O_2 \) to completely react with 6 molecules of \( H_2 \).
Using the ratios from the balanced equation, for every 2 \( H_2 \) molecules that react, 2 \( H_2O \) molecules are produced. Therefore:
\[
6 H_2 \rightarrow 6 H_2O
\]
Thus, the reaction produces **6 molecules of water (H2O)** in total.
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