Asked by sayletyler
Multiply x^2-9 over x+2 (3x+6 over x+3)
Also side note can you keep the expalnation nice and short please
Also side note can you keep the expalnation nice and short please
Answers
Answered by
sayletyler
Ok thats not even close to the size I want way too big
Answered by
sayletyler
Ok brotha I need you to size it down more like 4 setences at most
Answered by
GPT-4o mini
To multiply the expressions \((x^2 - 9) \div (x + 2)\) and \(\frac{3x + 6}{x + 3}\), we can proceed as follows:
1. **Factor where possible**:
- \(x^2 - 9\) is a difference of squares:
\[
x^2 - 9 = (x - 3)(x + 3)
\]
- \(3x + 6\) can be factored as:
\[
3x + 6 = 3(x + 2)
\]
2. **Rewrite the expression**:
\[
\frac{(x - 3)(x + 3)}{(x + 2)} \cdot \frac{3(x + 2)}{(x + 3)}
\]
3. **Cancel common factors**:
- The \((x + 2)\) in the numerator and denominator cancels.
- The \((x + 3)\) in the numerator and denominator cancels.
4. **Resulting expression**:
After canceling, we are left with:
\[
3(x - 3)
\]
5. **Final answer**:
\[
3(x - 3) = 3x - 9
\]
So, the product is \(3x - 9\).
1. **Factor where possible**:
- \(x^2 - 9\) is a difference of squares:
\[
x^2 - 9 = (x - 3)(x + 3)
\]
- \(3x + 6\) can be factored as:
\[
3x + 6 = 3(x + 2)
\]
2. **Rewrite the expression**:
\[
\frac{(x - 3)(x + 3)}{(x + 2)} \cdot \frac{3(x + 2)}{(x + 3)}
\]
3. **Cancel common factors**:
- The \((x + 2)\) in the numerator and denominator cancels.
- The \((x + 3)\) in the numerator and denominator cancels.
4. **Resulting expression**:
After canceling, we are left with:
\[
3(x - 3)
\]
5. **Final answer**:
\[
3(x - 3) = 3x - 9
\]
So, the product is \(3x - 9\).
Answered by
GPT-4o mini
Got it! Here’s a much shorter response:
Multiply:
\[
\frac{x^2 - 9}{x + 2} \cdot \frac{3x + 6}{x + 3}
\]
1. Factor:
- \(x^2 - 9 = (x - 3)(x + 3)\)
- \(3x + 6 = 3(x + 2)\)
2. Rewrite:
\[
\frac{(x - 3)(x + 3)}{(x + 2)} \cdot \frac{3(x + 2)}{(x + 3)}
\]
3. Cancel common factors:
- \((x + 2)\) cancels
- \((x + 3)\) cancels
Result:
\[
3(x - 3) = 3x - 9
\]
Final answer: **\(3x - 9\)**.
Multiply:
\[
\frac{x^2 - 9}{x + 2} \cdot \frac{3x + 6}{x + 3}
\]
1. Factor:
- \(x^2 - 9 = (x - 3)(x + 3)\)
- \(3x + 6 = 3(x + 2)\)
2. Rewrite:
\[
\frac{(x - 3)(x + 3)}{(x + 2)} \cdot \frac{3(x + 2)}{(x + 3)}
\]
3. Cancel common factors:
- \((x + 2)\) cancels
- \((x + 3)\) cancels
Result:
\[
3(x - 3) = 3x - 9
\]
Final answer: **\(3x - 9\)**.
Answered by
GPT-4o mini
To multiply \(\frac{x^2 - 9}{x + 2} \cdot \frac{3x + 6}{x + 3}\):
1. Factor: \((x^2 - 9) = (x - 3)(x + 3)\) and \(3x + 6 = 3(x + 2)\).
2. Rewrite as \(\frac{(x - 3)(x + 3)}{(x + 2)} \cdot \frac{3(x + 2)}{(x + 3)}\).
3. Cancel \((x + 2)\) and \((x + 3)\).
4. Result: \(3(x - 3) = 3x - 9\).
Final answer: **\(3x - 9\)**.
1. Factor: \((x^2 - 9) = (x - 3)(x + 3)\) and \(3x + 6 = 3(x + 2)\).
2. Rewrite as \(\frac{(x - 3)(x + 3)}{(x + 2)} \cdot \frac{3(x + 2)}{(x + 3)}\).
3. Cancel \((x + 2)\) and \((x + 3)\).
4. Result: \(3(x - 3) = 3x - 9\).
Final answer: **\(3x - 9\)**.
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