Use the properties of operations and rules for multiplying and dividing to solve:

(−35)×(516)×(712)÷(−316)×(−57)


(1 point)

1 answer

To solve the expression \((−35)×(516)×(712)÷(−316)×(−57)\), we can first rearrange the expression and apply the rules of multiplication and division.

  1. Combine the multiplication and division parts: \[ (−35) × (516) × (712) ÷ (−316) × (−57) = \frac{(−35) × (516) × (712)}{(−316) × (−57)} \]

  2. Determine the signs:

  • The product of two negative numbers (−316 and −57) is positive.
  • The numerator has one negative number (−35), so the overall numerator is negative.
  1. Simplify the sign to: \[ -\frac{(35) × (516) × (712)}{(316) × (57)} \]

  2. Perform the multiplications in the numerator and the denominator:

Numerator: \[ 35 × 516 × 712 \] Calculating step by step:

  • \(35 × 516 = 18180\)
  • \(18180 × 712 = 12920016\)

Denominator: \[ 316 × 57 \] Calculating step by step:

  • \(316 × 57 = 18012\)
  1. Now we have: \[ -\frac{12920016}{18012} \]

  2. Perform the division: Calculating \(12920016 ÷ 18012\):

After performing the division, we find: \[ 12920016 ÷ 18012 \approx 716 \]

Thus, the complete expression evaluates to: \[ -716 \]

Therefore, the final answer is: \[ \boxed{-716} \]