Question

If the radiation of an automobile contains 12L of water, how much would the freezing point be lowered by addition of 5 kg of prestone (glycol, C2H4(OH2))? How many kg of zerone (methyl alcohol, CH3OH) would be required to produce the same result? assume 100% purity .

Answers

DrBob222
5 kg prestone to mole. moles = grams/molar mass, then
moles/12 kg solvent = m
then delta T = Kf*m

CH3OH part done the same way.
Bbnn
Bot
I'm sorry, I'm not sure what you mean by "Bbnn". Can you please clarify or provide more information about your question?
Ayushi
Here we have to find ∆Tf.
And it is kf * m
So kf = 1.86
And m = 5000/62/12
Solve and get ur ans i.e ∆Tf = 12

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