Question
If a football player passes a football from 4 feet off the ground with an initial velocity of 6 feet per second, how long will it take the football to hit the ground? Use the equation h = −16t2 + 6t + 4. Round your answer to the nearest hundredth.
0.72
0.65
0.35
0.27
0.72
0.65
0.35
0.27
Answers
GPT-4o mini
To find the time it takes for the football to hit the ground, we need to solve the equation \( h = -16t^2 + 6t + 4 \) for \( h = 0 \) (when the football hits the ground).
We set up the equation:
\[
-16t^2 + 6t + 4 = 0
\]
Now, we can use the quadratic formula, which is:
\[
t = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
\]
In our equation, \( a = -16 \), \( b = 6 \), and \( c = 4 \).
First, we calculate the discriminant:
\[
b^2 - 4ac = 6^2 - 4(-16)(4) = 36 + 256 = 292
\]
Now we apply the quadratic formula:
\[
t = \frac{-6 \pm \sqrt{292}}{2(-16)}
\]
Calculating \( \sqrt{292} \):
\[
\sqrt{292} \approx 17.09
\]
Now substituting back into the quadratic formula:
\[
t = \frac{-6 \pm 17.09}{-32}
\]
This gives us two possible solutions for \( t \):
1.
\[
t = \frac{-6 + 17.09}{-32} = \frac{11.09}{-32} \approx -0.346
\]
(This value is negative and thus not a valid solution since time cannot be negative.)
2.
\[
t = \frac{-6 - 17.09}{-32} = \frac{-23.09}{-32} \approx 0.722
\]
We round \( 0.722 \) to the nearest hundredth:
\[
t \approx 0.72
\]
Thus, the time it takes for the football to hit the ground is **0.72 seconds**.
We set up the equation:
\[
-16t^2 + 6t + 4 = 0
\]
Now, we can use the quadratic formula, which is:
\[
t = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
\]
In our equation, \( a = -16 \), \( b = 6 \), and \( c = 4 \).
First, we calculate the discriminant:
\[
b^2 - 4ac = 6^2 - 4(-16)(4) = 36 + 256 = 292
\]
Now we apply the quadratic formula:
\[
t = \frac{-6 \pm \sqrt{292}}{2(-16)}
\]
Calculating \( \sqrt{292} \):
\[
\sqrt{292} \approx 17.09
\]
Now substituting back into the quadratic formula:
\[
t = \frac{-6 \pm 17.09}{-32}
\]
This gives us two possible solutions for \( t \):
1.
\[
t = \frac{-6 + 17.09}{-32} = \frac{11.09}{-32} \approx -0.346
\]
(This value is negative and thus not a valid solution since time cannot be negative.)
2.
\[
t = \frac{-6 - 17.09}{-32} = \frac{-23.09}{-32} \approx 0.722
\]
We round \( 0.722 \) to the nearest hundredth:
\[
t \approx 0.72
\]
Thus, the time it takes for the football to hit the ground is **0.72 seconds**.