To make the first graph (the proportional one which represents the function \( y = 12x \)) a non-proportional graph with the same y-intercept as the second graph (which is \( y = 11x + 20 \)), you want to add a fixed amount (a vertical shift) to the value of \( y \).
The first graph has a y-intercept of 0 because it is proportional, and the second graph has a y-intercept of 20 due to the setup fee.
To shift the graph of the first equation (which starts at (0,0)) up to a y-intercept of 20, you need to add 20 to the existing function \( y = 12x \). Therefore, the new function would be \( y = 12x + 20 \), which gives it a non-proportional characteristic due to the added constant.
Thus, the answer is:
E. Up 20.