Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
Simplify the polynomial expression (xy−2)(x2+1) .(2 points) []x^3y+[] x^2+ xy+[]Question
Simplify the polynomial expression (xy−2)(x^2+1)
.(2 points)
_x^3 y+_x2+_xy+_
.(2 points)
_x^3 y+_x2+_xy+_
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To simplify the expression \((xy - 2)(x^2 + 1)\), we will use the distributive property (also known as the FOIL method for binomials).
1. Distribute \(xy\) across \(x^2 + 1\):
\[
xy \cdot x^2 + xy \cdot 1 = xyx^2 + xy = x^3y + xy
\]
2. Distribute \(-2\) across \(x^2 + 1\):
\[
-2 \cdot x^2 + -2 \cdot 1 = -2x^2 - 2
\]
3. Now, combine all the terms:
\[
x^3y + xy - 2x^2 - 2
\]
Putting it all together, the simplified form of the polynomial expression is:
\[
x^3y - 2x^2 + xy - 2
\]
Therefore, filling in the blanks for your polynomial expression:
- The coefficient for \(x^3y\) is **1**.
- The coefficient for \(x^2\) is **-2**.
- The coefficient for \(xy\) is **1**.
- The constant term is **-2**.
So the final answer is:
\[
1 \, x^3 y - 2 \, x^2 + 1 \, xy - 2
\]
1. Distribute \(xy\) across \(x^2 + 1\):
\[
xy \cdot x^2 + xy \cdot 1 = xyx^2 + xy = x^3y + xy
\]
2. Distribute \(-2\) across \(x^2 + 1\):
\[
-2 \cdot x^2 + -2 \cdot 1 = -2x^2 - 2
\]
3. Now, combine all the terms:
\[
x^3y + xy - 2x^2 - 2
\]
Putting it all together, the simplified form of the polynomial expression is:
\[
x^3y - 2x^2 + xy - 2
\]
Therefore, filling in the blanks for your polynomial expression:
- The coefficient for \(x^3y\) is **1**.
- The coefficient for \(x^2\) is **-2**.
- The coefficient for \(xy\) is **1**.
- The constant term is **-2**.
So the final answer is:
\[
1 \, x^3 y - 2 \, x^2 + 1 \, xy - 2
\]
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.