Question

Which falling object will result in the least kinetic energy when it collides with the ground?(1 point)
Responses

10 grams of water falling at 1 m/s
10 grams of water falling at 1 m/s

100 grams of dirt falling at 15 m/s
100 grams of dirt falling at 15 m/s

100 grams of water falling at 10 m/s
100 grams of water falling at 10 m/s

10 grams of dirt falling at 2 m/s

Answer 1

To determine which falling object will result in the least kinetic energy when it collides with the ground, we can use the formula for kinetic energy (KE):

\[ KE = \frac{1}{2} mv^2 \]

where:
- \( m \) is the mass of the object (in kilograms),
- \( v \) is the velocity of the object (in meters per second).

Let's calculate the kinetic energy for each option:

1. **10 grams of water falling at 1 m/s:**
- Mass (m) = 10 grams = 0.01 kg
- Velocity (v) = 1 m/s
- KE = \( \frac{1}{2} \times 0.01 \times (1)^2 = 0.005 \, \text{J} \)

2. **100 grams of dirt falling at 15 m/s:**
- Mass (m) = 100 grams = 0.1 kg
- Velocity (v) = 15 m/s
- KE = \( \frac{1}{2} \times 0.1 \times (15)^2 = \frac{1}{2} \times 0.1 \times 225 = 11.25 \, \text{J} \)

3. **100 grams of water falling at 10 m/s:**
- Mass (m) = 100 grams = 0.1 kg
- Velocity (v) = 10 m/s
- KE = \( \frac{1}{2} \times 0.1 \times (10)^2 = \frac{1}{2} \times 0.1 \times 100 = 5 \, \text{J} \)

4. **10 grams of dirt falling at 2 m/s:**
- Mass (m) = 10 grams = 0.01 kg
- Velocity (v) = 2 m/s
- KE = \( \frac{1}{2} \times 0.01 \times (2)^2 = \frac{1}{2} \times 0.01 \times 4 = 0.02 \, \text{J} \)

Now, let's summarize the kinetic energies calculated:

- 10 grams of water at 1 m/s = 0.005 J
- 100 grams of dirt at 15 m/s = 11.25 J
- 100 grams of water at 10 m/s = 5 J
- 10 grams of dirt at 2 m/s = 0.02 J

The object with the least kinetic energy is:

**10 grams of water falling at 1 m/s (0.005 J).**