To solve the compound inequality \(-7 \leq 2x + 1 < 11\), we can break it down into two parts:
- \(-7 \leq 2x + 1\)
- \(2x + 1 < 11\)
Let's solve each part separately.
Part 1: \(-7 \leq 2x + 1\)
Subtract 1 from both sides:
\[ -7 - 1 \leq 2x \]
\[ -8 \leq 2x \]
Now, divide both sides by 2 (note that we do not flip the inequality here since we are dividing by a positive number):
\[ -4 \leq x \]
This can also be written as:
\[ x \geq -4 \]
Part 2: \(2x + 1 < 11\)
Subtract 1 from both sides:
\[ 2x < 11 - 1 \]
\[ 2x < 10 \]
Now, divide both sides by 2:
\[ x < 5 \]
Combining the Results
Now we can combine our results from both parts:
\[ -4 \leq x < 5 \]
Number Line Representation
To represent the solution \(-4 \leq x < 5\) on a number line:
- Place a closed circle on -4 (indicating that it is included).
- Place an open circle on 5 (indicating that it is not included).
- Shade the region between -4 and 5.
This gives us the correct representation of the solution on the number line.