The equation \( \frac{5}{b} = 10 \) can be rewritten as two equations joined by "and" as follows:
\( \frac{5}{b} = 10 \) and \( b \neq 0 \)
as two equations joined by “and.”(1 point)
5/b=10
and b≠
11 answers
The equation \( \frac{5}{b} = 10 \) can be rewritten as two equations joined by "and" as follows:
\( \frac{5}{b} = 10 \) and \( b \neq 0 \)
To solve the equation \( \frac{15}{3x} - 9 - 4 = 12 \), we will first simplify and find the value of \( x \).
Start by combining the constants: \[ -9 - 4 = -13 \] So the equation becomes: \[ \frac{15}{3x} - 13 = 12 \]
Now, add 13 to both sides to isolate the fraction: \[ \frac{15}{3x} = 12 + 13 \] \[ \frac{15}{3x} = 25 \]
Next, multiply both sides by \( 3x \) to eliminate the fraction: \[ 15 = 25 \cdot 3x \] \[ 15 = 75x \]
Now, solve for \( x \) by dividing both sides by 75: \[ x = \frac{15}{75} = \frac{1}{5} \]
Now we need to specify the condition \( x \neq \) something. Since division by zero is undefined, we must ensure that \( 3x \neq 0 \). Therefore, \( x \neq 0 \) is the condition.
So we can summarize the answer as follows:
The value that completes the set of equations is \( x = \frac{1}{5} \) and \( x \neq 0 \).
The fraction \( \frac{15}{3x} \) becomes undefined when the denominator is equal to zero.
To find that value of \( x \), set the denominator equal to zero:
\[ 3x = 0 \]
Now, solve for \( x \):
\[ x = 0 \]
Therefore, the value that would cause the fraction \( \frac{15}{3x} - 9 \) to be undefined is:
\( x \neq 0 \)
To determine the value that makes the expression undefined for the equation
\[ 22 = \frac{4 + 5x}{9x - 6} \]
we need to identify when the denominator is equal to zero, since division by zero is undefined.
The denominator of the fraction is \( 9x - 6 \). Set this equal to zero and solve for \( x \):
\[ 9x - 6 = 0 \]
Adding 6 to both sides gives:
\[ 9x = 6 \]
Now, divide both sides by 9:
\[ x = \frac{6}{9} \]
This fraction can be reduced:
\[ x = \frac{2}{3} \]
Thus, the value that makes the expression undefined is:
\[ x = \frac{2}{3} \]
To solve the equation
\[ \frac{1}{x} + 4 = 2, \]
first, isolate the term involving \( x \) by subtracting 4 from both sides:
\[ \frac{1}{x} = 2 - 4, \] \[ \frac{1}{x} = -2. \]
Next, take the reciprocal of both sides to solve for \( x \):
\[ x = \frac{1}{-2}. \]
Thus, the solution is
\[ x = -\frac{1}{2}. \]
So, \( x = -\frac{1}{2} \) is your answer in reduced fraction form.
To solve the equation
\[ \frac{17}{p} + 4 = 55, \]
first, isolate the term with \( p \) by subtracting 4 from both sides:
\[ \frac{17}{p} = 55 - 4, \]
which simplifies to:
\[ \frac{17}{p} = 51. \]
Next, multiply both sides by \( p \) to eliminate the fraction:
\[ 17 = 51p. \]
Now, solve for \( p \) by dividing both sides by 51:
\[ p = \frac{17}{51}. \]
The fraction \( \frac{17}{51} \) can be reduced. The greatest common divisor (GCD) of 17 and 51 is 17. Thus:
\[ p = \frac{1}{3}. \]
So, the value of \( p \) in reduced fraction form is
\[ p = \frac{1}{3}. \]