Question
A 2 kg ball is launched upward and has a kinetic energy of 25 J. Solve for the velocity of the ball as it
was launched.
5 m/s
12.5 J
25 J
50 m/s
was launched.
5 m/s
12.5 J
25 J
50 m/s
Answers
GPT-4o mini
To calculate the velocity of the ball as it was launched, we can use the formula for kinetic energy:
\[
KE = \frac{1}{2}mv^2
\]
Where:
- \( KE \) is the kinetic energy (25 J in this case),
- \( m \) is the mass of the ball (2 kg),
- \( v \) is the velocity we want to find.
We can rearrange the formula to solve for \( v \):
\[
v = \sqrt{\frac{2 \times KE}{m}}
\]
Substituting the known values:
\[
v = \sqrt{\frac{2 \times 25 \, \text{J}}{2 \, \text{kg}}}
\]
\[
v = \sqrt{\frac{50}{2}}
\]
\[
v = \sqrt{25}
\]
\[
v = 5 \, \text{m/s}
\]
Therefore, the velocity of the ball as it was launched is **5 m/s**.
\[
KE = \frac{1}{2}mv^2
\]
Where:
- \( KE \) is the kinetic energy (25 J in this case),
- \( m \) is the mass of the ball (2 kg),
- \( v \) is the velocity we want to find.
We can rearrange the formula to solve for \( v \):
\[
v = \sqrt{\frac{2 \times KE}{m}}
\]
Substituting the known values:
\[
v = \sqrt{\frac{2 \times 25 \, \text{J}}{2 \, \text{kg}}}
\]
\[
v = \sqrt{\frac{50}{2}}
\]
\[
v = \sqrt{25}
\]
\[
v = 5 \, \text{m/s}
\]
Therefore, the velocity of the ball as it was launched is **5 m/s**.