Question
The following values are collected from an experiment
y
33
38.4
46.2
What type of relationship exists between the x and y values?
(1 point)
O Linear
O Quadratic
OTriangular
O Irregular
X
5.5
6.4
7.7
y
33
38.4
46.2
What type of relationship exists between the x and y values?
(1 point)
O Linear
O Quadratic
OTriangular
O Irregular
X
5.5
6.4
7.7
Answers
GPT-4o mini
To determine the type of relationship between the x and y values, we can examine the values presented:
- **x values:** 5.5, 6.4, 7.7
- **y values:** 33, 38.4, 46.2
We can check the pattern in y-values relative to x-values.
1. Calculate the difference in y values and the difference in x values:
- Between the first and second points:
- \( y: 38.4 - 33 = 5.4 \)
- \( x: 6.4 - 5.5 = 0.9 \)
- Between the second and third points:
- \( y: 46.2 - 38.4 = 7.8 \)
- \( x: 7.7 - 6.4 = 1.3 \)
2. Now calculate the slopes between these points:
- Slope between the first and second points:
\(\frac{5.4}{0.9} = 6\)
- Slope between the second and third points:
\(\frac{7.8}{1.3} \approx 6\)
The slopes are approximately constant. This suggests a linear relationship, as the changes in y are proportional to the changes in x.
Therefore, the type of relationship that exists between the x and y values is:
**Linear** (First option).
- **x values:** 5.5, 6.4, 7.7
- **y values:** 33, 38.4, 46.2
We can check the pattern in y-values relative to x-values.
1. Calculate the difference in y values and the difference in x values:
- Between the first and second points:
- \( y: 38.4 - 33 = 5.4 \)
- \( x: 6.4 - 5.5 = 0.9 \)
- Between the second and third points:
- \( y: 46.2 - 38.4 = 7.8 \)
- \( x: 7.7 - 6.4 = 1.3 \)
2. Now calculate the slopes between these points:
- Slope between the first and second points:
\(\frac{5.4}{0.9} = 6\)
- Slope between the second and third points:
\(\frac{7.8}{1.3} \approx 6\)
The slopes are approximately constant. This suggests a linear relationship, as the changes in y are proportional to the changes in x.
Therefore, the type of relationship that exists between the x and y values is:
**Linear** (First option).