To determine if \( \frac{2}{6} \) is less than \( \frac{1}{2} \), we can simplify \( \frac{2}{6} \) first.
Simplifying \( \frac{2}{6} \): \[ \frac{2}{6} = \frac{1}{3} \]
Now we compare \( \frac{1}{3} \) and \( \frac{1}{2} \).
To compare these fractions, we can find a common denominator, which in this case would be 6:
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Convert \( \frac{1}{3} \) to sixths: \[ \frac{1}{3} = \frac{2}{6} \]
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Convert \( \frac{1}{2} \) to sixths: \[ \frac{1}{2} = \frac{3}{6} \]
Now we compare the two fractions: \[ \frac{2}{6} < \frac{3}{6} \]
This means: \[ \frac{1}{3} < \frac{1}{2} \]
So, \( \frac{2}{6} \) (which is equivalent to \( \frac{1}{3} \)) is indeed less than \( \frac{1}{2} \).