To compare \( \frac{3}{8} \) and \( \frac{1}{2} \), it can be helpful to convert \( \frac{1}{2} \) to a fraction with a denominator of 8:
\[ \frac{1}{2} = \frac{1 \times 4}{2 \times 4} = \frac{4}{8} \]
Now, we can compare \( \frac{3}{8} \) and \( \frac{4}{8} \):
Since \( 3 < 4 \), we have:
\[ \frac{3}{8} < \frac{4}{8} \]
Therefore, \( \frac{3}{8} \) is less than \( \frac{1}{2} \).
So, \( \frac{3}{8} \) is not greater than \( \frac{1}{2} \).