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Using the ten percent rule, determine how many kilocalories of energy the tertiary consumer tuna will receive. Algae Shrimp Lan...Question
Using the ten percent rule, determine how many kilocalories of energy the tertiary consumer tuna will receive.
Algae Shrimp Lantern Fish Tuna
135,000 Kcal
(1 point)
Responses
135 Kcal
135 Kcal
13,500 Kcal
13,500 Kcal
135,000 Kcal
135,000 Kcal
1,350 Kcal
Algae Shrimp Lantern Fish Tuna
135,000 Kcal
(1 point)
Responses
135 Kcal
135 Kcal
13,500 Kcal
13,500 Kcal
135,000 Kcal
135,000 Kcal
1,350 Kcal
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To apply the ten percent rule in an ecological pyramid, we can determine how much energy each trophic level receives from the previous one.
Starting with the producers (algae), which have 135,000 Kcal:
1. **Algae to Shrimp (Primary Consumer)** - The shrimp will receive 10% of the energy from the algae:
\[
135,000 \text{ Kcal} \times 0.10 = 13,500 \text{ Kcal}
\]
2. **Shrimp to Lantern Fish (Secondary Consumer)** - The lantern fish will receive 10% of the energy from the shrimp:
\[
13,500 \text{ Kcal} \times 0.10 = 1,350 \text{ Kcal}
\]
3. **Lantern Fish to Tuna (Tertiary Consumer)** - Finally, the tuna will receive 10% of the energy from the lantern fish:
\[
1,350 \text{ Kcal} \times 0.10 = 135 \text{ Kcal}
\]
So, the tuna will receive **135 Kcal** of energy.
The correct response is **135 Kcal**.
Starting with the producers (algae), which have 135,000 Kcal:
1. **Algae to Shrimp (Primary Consumer)** - The shrimp will receive 10% of the energy from the algae:
\[
135,000 \text{ Kcal} \times 0.10 = 13,500 \text{ Kcal}
\]
2. **Shrimp to Lantern Fish (Secondary Consumer)** - The lantern fish will receive 10% of the energy from the shrimp:
\[
13,500 \text{ Kcal} \times 0.10 = 1,350 \text{ Kcal}
\]
3. **Lantern Fish to Tuna (Tertiary Consumer)** - Finally, the tuna will receive 10% of the energy from the lantern fish:
\[
1,350 \text{ Kcal} \times 0.10 = 135 \text{ Kcal}
\]
So, the tuna will receive **135 Kcal** of energy.
The correct response is **135 Kcal**.
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