Asked by Smartypants
C=1/6 πv^r solve for r
Answers
Answered by
GPT-4o mini
To solve the equation \( C = \frac{1}{6} \pi v^r \) for \( r \), follow these steps:
1. **Multiply both sides by 6 to eliminate the fraction:**
\[
6C = \pi v^r
\]
2. **Divide both sides by \( \pi \):**
\[
\frac{6C}{\pi} = v^r
\]
3. **Take the logarithm of both sides. You can use any logarithm (common logarithm or natural logarithm). Here, we will use natural logarithm (ln):**
\[
\ln\left(\frac{6C}{\pi}\right) = \ln(v^r)
\]
4. **Use the property of logarithms that states \(\ln(a^b) = b \cdot \ln(a)\):**
\[
\ln\left(\frac{6C}{\pi}\right) = r \ln(v)
\]
5. **Finally, solve for \( r \):**
\[
r = \frac{\ln\left(\frac{6C}{\pi}\right)}{\ln(v)}
\]
So, the solution for \( r \) is:
\[
r = \frac{\ln\left(\frac{6C}{\pi}\right)}{\ln(v)}
\]
1. **Multiply both sides by 6 to eliminate the fraction:**
\[
6C = \pi v^r
\]
2. **Divide both sides by \( \pi \):**
\[
\frac{6C}{\pi} = v^r
\]
3. **Take the logarithm of both sides. You can use any logarithm (common logarithm or natural logarithm). Here, we will use natural logarithm (ln):**
\[
\ln\left(\frac{6C}{\pi}\right) = \ln(v^r)
\]
4. **Use the property of logarithms that states \(\ln(a^b) = b \cdot \ln(a)\):**
\[
\ln\left(\frac{6C}{\pi}\right) = r \ln(v)
\]
5. **Finally, solve for \( r \):**
\[
r = \frac{\ln\left(\frac{6C}{\pi}\right)}{\ln(v)}
\]
So, the solution for \( r \) is:
\[
r = \frac{\ln\left(\frac{6C}{\pi}\right)}{\ln(v)}
\]
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