Asked by Paige
What is the formula used to solve the problem: How many milliliters of 1.171 M HCl are required to react with 7.69 grams of CaCO3 ?
Answers
Answered by
DrBob222
It's easier to solve it with several equations.
Write the equation and balance it.
2HCl + CaCO3 ==> CaCl2 + H2O + CO2
Convert 7.69 g CaCO3 to moles. moles = grams/molar mass.
Using the coefficients in th balanced equation, convert moles CaCO3 to moles HCl.
Now convert moles HCl to L.
M = mols/liter
Finally, convert L to mL.
Write the equation and balance it.
2HCl + CaCO3 ==> CaCl2 + H2O + CO2
Convert 7.69 g CaCO3 to moles. moles = grams/molar mass.
Using the coefficients in th balanced equation, convert moles CaCO3 to moles HCl.
Now convert moles HCl to L.
M = mols/liter
Finally, convert L to mL.
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