Asked by Water

C = 3/2(k - 91) solve for k

Answers

Answered by Water
simplify
Answered by Water
What is the answer without the brackets in normal form
Answered by Water
Solve the equation for m. mp + mq = x
Answered by Water
What is the answer in normal form
Answered by GPT-4o mini
To solve the equation \( C = \frac{3}{2}(k - 91) \) for \( k \), follow these steps:

1. Start by multiplying both sides by \( \frac{2}{3} \) to eliminate the fraction:

\[
\frac{2}{3}C = k - 91
\]

2. Next, isolate \( k \) by adding \( 91 \) to both sides:

\[
k = \frac{2}{3}C + 91
\]

Thus, the solution for \( k \) is:

\[
k = \frac{2}{3}C + 91
\]
Answered by GPT-4o mini
The expression for \( k \) is:

\[
k = \frac{2}{3}C + 91
\]

This expression is already in a simplified form, combining the fraction and the constant. However, if you want to express it in a single fraction, you can find a common denominator.

To combine \( \frac{2}{3}C \) and \( 91 \) into a single fraction, convert \( 91 \) to a fraction with a denominator of \( 3 \):

\[
91 = \frac{273}{3}
\]

Now you can write:

\[
k = \frac{2C}{3} + \frac{273}{3} = \frac{2C + 273}{3}
\]

So, the simplified expression for \( k \) can also be written as:

\[
k = \frac{2C + 273}{3}
\]

This is another simplified form of the expression.
Answered by GPT-4o mini
To express \( k \) without brackets and in a more standard form, you can rewrite the expression:

Starting from the previously simplified formula:

\[
k = \frac{2C + 273}{3}
\]

There are a couple of ways you could express it in "normal form," but let’s remove the fraction and express it more explicitly:

1. You can keep it as is, or
2. Multiply through by 3 to eliminate the fraction:

\[
3k = 2C + 273
\]

Now, if you're looking for \( k \) in terms of \( C \) without brackets or fractions, the first form with brackets is often more common, while the second form could represent the direct relationship without a fraction.

If you prefer \( k \) isolated and written plainly (not with fractions):

So the answer in a "normal form" without fractions is:

\[
3k = 2C + 273
\]

Alternatively, if you want \( k \) isolated, you could express it as:

\[
k = \frac{2}{3}C + 91
\]

Both forms are valid depending on whether you wish to maintain fractions or not. Would you like me to clarify any further?
Answered by GPT-4o mini
To solve the equation \( mp + mq = x \) for \( m \), follow these steps:

1. Factor out \( m \) from the left side of the equation:

\[
m(p + q) = x
\]

2. Now, divide both sides by \( (p + q) \) (assuming \( p + q \neq 0 \)) to isolate \( m \):

\[
m = \frac{x}{p + q}
\]

Thus, the solution for \( m \) is:

\[
m = \frac{x}{p + q}
\]
Answered by GPT-4o mini
The solution for \( m \) derived from the equation \( mp + mq = x \) is:

\[
m = \frac{x}{p + q}
\]

In "normal form" (without fractions), we rearrange the equation. To eliminate the fraction, we can multiply both sides by \( (p + q) \):

Starting from:

\[
m = \frac{x}{p + q}
\]

Multiply both sides by \( (p + q) \):

\[
m(p + q) = x
\]

This is a valid form of the equation representing the same relationship, but rewritten without isolating \( m \) as a fraction.

If you are looking for either an equation or statement involving \( m \) that does not have a fraction, you can use:

\[
mp + mq = x
\]

So in "normal form," we can either keep it as \( m(p + q) = x \) or return to the original relationship, depending on the context. Would you like a specific form or another type of representation?

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