Question
Martin made a veggie pizza on a whole wheat crust he used 16 ounces of cheese he cut his pizza into 8 slices. In 1 oz of mozzarella cheese there are 72 calories and 0.79 carbohydrates. How many grams of carbohydrates from mozzarella cheese in each slice? A. 2.37 b. 9.48 c. 1.58 d. 0.79
Answers
GPT-4o mini
To find the number of grams of carbohydrates from mozzarella cheese in each slice of Martin's veggie pizza, we need to follow these steps:
1. **Determine the total carbohydrates in the cheese used:**
- Martin used 16 ounces of mozzarella cheese.
- Each ounce contains 0.79 grams of carbohydrates.
Total carbohydrates from the cheese:
\[
\text{Total carbohydrates} = \text{amount of cheese (oz)} \times \text{carbohydrates per oz}
\]
\[
= 16 \, \text{oz} \times 0.79 \, \text{g/oz} = 12.64 \, \text{g}
\]
2. **Calculate the carbohydrates per slice:**
- The pizza is divided into 8 slices, so we divide the total carbohydrates by the number of slices.
Carbohydrates per slice:
\[
\text{Carbohydrates per slice} = \frac{\text{Total carbohydrates}}{\text{Number of slices}}
\]
\[
= \frac{12.64 \, \text{g}}{8} = 1.58 \, \text{g}
\]
Thus, the number of grams of carbohydrates from mozzarella cheese in each slice is **1.58 grams**.
The answer is **c. 1.58**.
1. **Determine the total carbohydrates in the cheese used:**
- Martin used 16 ounces of mozzarella cheese.
- Each ounce contains 0.79 grams of carbohydrates.
Total carbohydrates from the cheese:
\[
\text{Total carbohydrates} = \text{amount of cheese (oz)} \times \text{carbohydrates per oz}
\]
\[
= 16 \, \text{oz} \times 0.79 \, \text{g/oz} = 12.64 \, \text{g}
\]
2. **Calculate the carbohydrates per slice:**
- The pizza is divided into 8 slices, so we divide the total carbohydrates by the number of slices.
Carbohydrates per slice:
\[
\text{Carbohydrates per slice} = \frac{\text{Total carbohydrates}}{\text{Number of slices}}
\]
\[
= \frac{12.64 \, \text{g}}{8} = 1.58 \, \text{g}
\]
Thus, the number of grams of carbohydrates from mozzarella cheese in each slice is **1.58 grams**.
The answer is **c. 1.58**.