Question

Compare 7.6 × 10^−25 and 6.7 × 10^−52 . Which statement is true?(1 point)
7.6 × 10^−25 < 6.7 × 10^−52
7.6 × 10^−25 ≤ 6.7 × 10^−52
7.6 × 10^−25 = 6.7 × 10^−52
7.6 × 10^−25 > 6.7 × 10^−52

Answer 1

To compare \(7.6 \times 10^{-25}\) and \(6.7 \times 10^{-52}\), we need to consider the scientific notation format, where the number's size is determined by both the coefficient and the exponent.

1. **Exponents**: The exponent in the first term is \(-25\) and in the second term it is \(-52\). Since \(-25\) is greater than \(-52\), this means \(10^{-25}\) is actually larger than \(10^{-52}\).

2. **Coefficients**: The coefficients are \(7.6\) and \(6.7\). However, since we have already established that \(10^{-25}\) is larger than \(10^{-52}\), we can directly compare the entire terms:

\[
7.6 \times 10^{-25} > 6.7 \times 10^{-52}
\]

Thus, the true statement is:

**7.6 × 10^−25 > 6.7 × 10^−52**.

Answer 2

are you sure

Answer 3

Yes, let's double-check the comparison step by step.

To compare \(7.6 \times 10^{-25}\) and \(6.7 \times 10^{-52}\):

1. **Identify the exponents**:
- The exponent of the first number is \(-25\).
- The exponent of the second number is \(-52\).

The smaller the exponent in scientific notation, the larger the value. Thus:
- \(10^{-25}\) is greater than \(10^{-52}\).

2. **Compare the values**:
\[
7.6 \times 10^{-25} \text{ (which is of order } 10^{-25})
\]
\[
6.7 \times 10^{-52} \text{ (which is of order } 10^{-52})
\]

Since \(10^{-25} > 10^{-52}\), we conclude that:

\[
7.6 \times 10^{-25} > 6.7 \times 10^{-52}
\]

**Final statement**:

Thus, the correct comparison is indeed:
**7.6 × 10^−25 > 6.7 × 10^−52**.

Thank you for your caution!