Consider the expression x+6/3^2−(2⋅3)+5

To simplify the given expression \( x + \frac{6}{3^2} - (2 \cdot 3) + 5 \), we first evaluate the denominator \( 3^2 \).

1. Calculate \( 3^2 \):
\[ 3^2 = 9 \]

2. Thus, the expression can be rewritten as:
\[ x + \frac{6}{9} - (2 \cdot 3) + 5 \]

3. Now calculate \( 2 \cdot 3 \):
\[ 2 \cdot 3 = 6 \]

The entire expression becomes:
\[ x + \frac{6}{9} - 6 + 5 \]

Now, simplify \( \frac{6}{9} \):
\[ \frac{6}{9} = \frac{2}{3} \]

Hence, the expression now is:
\[ x + \frac{2}{3} - 6 + 5 \]

The simplified denominator referred to in your question is \( 9 \) as \( 3^2 = 9 \).

Therefore, the simplified denominator is:
\[
\boxed{9}
\]