To determine the number of hydrogen atoms present after the reaction \( 2H_2 + O_2 \rightarrow 2H_2O \), let's analyze the reaction.
Before the reaction:
- The reactants consist of \( 2H_2 \) (which contains 2 molecules of hydrogen gas). Each molecule of \( H_2 \) has 2 hydrogen atoms, so: \[ 2 \text{ molecules of } H_2 \times 2 \text{ atoms/molecule} = 4 \text{ hydrogen atoms} \]
After the reaction:
- The products consist of \( 2H_2O \) (which contains 2 molecules of water). Each molecule of \( H_2O \) contains 2 hydrogen atoms as well, so: \[ 2 \text{ molecules of } H_2O \times 2 \text{ atoms/molecule} = 4 \text{ hydrogen atoms} \]
Thus, the number of hydrogen atoms present after the reaction is 4.
The correct response is 4.