Question
Use the equation to answer the question. 4NaCl+2SO2+_____ H2O+_____ O2→_____ Na2SO4+4HCl Which represents the balanced equation? (1 point) Responses 4NaCl+2SO2+H2O+2O2→ 2Na2SO4+4HCl 4 N a C l plus 2 S O sub 2 plus H sub 2 O plus 2 O sub 2 rightarrow 2 N a sub 2 S O sub 4 plus 4 H C l 4NaCl+2SO2+2H2O+O2→ 2Na2SO4+4HCl 4 N a C l plus 2 S O sub 2 plus 2 H sub 2 O plus O sub 2 rightarrow 2 N a sub 2 S O sub 4 plus 4 H C l 4NaCl+2SO2+2H2O+O2→ 4Na2SO4+4HCl 4 N a C l plus 2 S O sub 2 plus 2 H sub 2 O plus O sub 2 rightarrow 4 N a sub 2 S O sub 4 plus 4 H C l 4NaCl+2SO2+H2O+2O2→ 4Na2SO4+4HCl
Answers
GPT-4o mini
To balance the chemical equation \( 4NaCl + 2SO_2 + \_\_ H_2O + \_\_ O_2 \rightarrow \_\_ Na_2SO_4 + 4HCl \), we need to ensure that the number of atoms for each element is the same on both sides of the equation.
Let's analyze the original unbalanced equation:
- **Reactants**:
- \( Na \): 4 (from \( 4NaCl \))
- \( Cl \): 4 (from \( 4NaCl \))
- \( S \): 2 (from \( 2SO_2 \))
- \( O \): 4 (2 from each \( SO_2 \), total of 4)
- \( H \): needs to be determined based on what is produced
- **Products**:
- Each \( Na_2SO_4 \) contains 2 Na and 1 S, so from \( \_\_ Na_2SO_4 \), we can conclude that we will need 2 moles for the given 4 Na (this means we need 2\( Na_2SO_4 \)).
- Each \( Na_2SO_4 \) also contributes 4 O (so with 2 moles, we get 8 O)
- There are 4 \( HCl \) contributing 4 Cl (which matches the 4 Cl from the reactants)
From this, the products can be seen as:
- For \( 2Na_2SO_4 \), we get 2S and 8O (from two \( Na_2SO_4 \))
- For \( 4HCl \), we get 4H and 4Cl.
Now for the water and oxygen:
1. We need 4 H from the \( HCl \), which means we need 2 \( H_2O \) to provide the required hydrogen.
2. The total number of oxygen atoms required on the product side should be:
- 8 from \( Na_2SO_4 \)
- 4 from \( HCl \)
- That means we need a total of 12 O atoms on the reactant side.
- Right now, we have 4 (from \( 2SO_2 \)) plus 2 from \( H_2O \) plus \( O_2 \) needs.
Now let's put the equation together:
- \( 4NaCl + 2SO_2 + 2H_2O + O_2 \rightarrow 2Na_2SO_4 + 4HCl \)
So the correct answer is:
4NaCl + 2SO2 + 2H2O + O2 → 2Na2SO4 + 4HCl
Let's analyze the original unbalanced equation:
- **Reactants**:
- \( Na \): 4 (from \( 4NaCl \))
- \( Cl \): 4 (from \( 4NaCl \))
- \( S \): 2 (from \( 2SO_2 \))
- \( O \): 4 (2 from each \( SO_2 \), total of 4)
- \( H \): needs to be determined based on what is produced
- **Products**:
- Each \( Na_2SO_4 \) contains 2 Na and 1 S, so from \( \_\_ Na_2SO_4 \), we can conclude that we will need 2 moles for the given 4 Na (this means we need 2\( Na_2SO_4 \)).
- Each \( Na_2SO_4 \) also contributes 4 O (so with 2 moles, we get 8 O)
- There are 4 \( HCl \) contributing 4 Cl (which matches the 4 Cl from the reactants)
From this, the products can be seen as:
- For \( 2Na_2SO_4 \), we get 2S and 8O (from two \( Na_2SO_4 \))
- For \( 4HCl \), we get 4H and 4Cl.
Now for the water and oxygen:
1. We need 4 H from the \( HCl \), which means we need 2 \( H_2O \) to provide the required hydrogen.
2. The total number of oxygen atoms required on the product side should be:
- 8 from \( Na_2SO_4 \)
- 4 from \( HCl \)
- That means we need a total of 12 O atoms on the reactant side.
- Right now, we have 4 (from \( 2SO_2 \)) plus 2 from \( H_2O \) plus \( O_2 \) needs.
Now let's put the equation together:
- \( 4NaCl + 2SO_2 + 2H_2O + O_2 \rightarrow 2Na_2SO_4 + 4HCl \)
So the correct answer is:
4NaCl + 2SO2 + 2H2O + O2 → 2Na2SO4 + 4HCl