Question

2. Solve x2=289
by inspection. There are two real solutions. Enter the lesser number first.(2 points)
{
,
}

Answer 1

To solve the equation \( x^2 = 289 \) by inspection, we need to find the values of \( x \) that satisfy this equation.

Taking the square root of both sides, we find:
\[
x = \pm \sqrt{289}
\]
Calculating the square root:
\[
\sqrt{289} = 17
\]
Thus, the two solutions are:
\[
x = 17 \quad \text{and} \quad x = -17
\]

Since we need to enter the lesser number first, the solutions are:
\[
\{-17, 17\}
\]