Asked by Luc
A gas sample containing only SO3, CH2O and C2H6O2 has the following mass percent composition: 65.1% SO3 and 8.79% CH2O. Calculate the partial pressure (torr) of SO3 if the total pressure of the sample is 4712 torr.
Unit conversion
K = C + 273
1 atm = 760 torr
Molar Mass (g/mol)
SO3 80.063
CH2O 30.026
C2H6O2 62.068
Unit conversion
K = C + 273
1 atm = 760 torr
Molar Mass (g/mol)
SO3 80.063
CH2O 30.026
C2H6O2 62.068
Answers
Answered by
DrBob222
I would convert the percent composition of the gas to mole fractions, then
P<sub>SO<sub>3</sub></sub> = X<sub>SO<sub>3</sub></sub>*P<sub>total</sub>
P<sub>SO<sub>3</sub></sub> = X<sub>SO<sub>3</sub></sub>*P<sub>total</sub>
Answered by
Luc
I came up with 3461 torr, but the homework program I am using said that the correct answer is 2510 torr. So, I either did something wrong, or the method provided above does not work
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