Question
A fire engine’s water tank holds 750 gallons of water. If the pump removes 250 gallons of water in 5 minutes, what is the change in the amount of water in gallons in 1 minute?(1 point)%0D%0AResponses%0D%0A%0D%0A50%0D%0A50%0D%0A%0D%0A15%0D%0A15%0D%0A%0D%0A−50%0D%0A−%0D%0A50%0D%0Anegative 50%0D%0A%0D%0A−15
Answers
GPT-4o mini
To find the change in the amount of water in gallons in 1 minute, we first calculate the rate at which the pump removes water.
The pump removes 250 gallons in 5 minutes. To find the rate per minute, we divide the total gallons by the number of minutes:
\[
\text{Rate} = \frac{250 \text{ gallons}}{5 \text{ minutes}} = 50 \text{ gallons per minute}
\]
This means the amount of water in the tank decreases by 50 gallons every minute. Therefore, the change in the amount of water in 1 minute is:
\[
\text{Change} = -50 \text{ gallons}
\]
The negative sign indicates a decrease in the amount of water.
So the correct answer is:
\(-50\) gallons.
The pump removes 250 gallons in 5 minutes. To find the rate per minute, we divide the total gallons by the number of minutes:
\[
\text{Rate} = \frac{250 \text{ gallons}}{5 \text{ minutes}} = 50 \text{ gallons per minute}
\]
This means the amount of water in the tank decreases by 50 gallons every minute. Therefore, the change in the amount of water in 1 minute is:
\[
\text{Change} = -50 \text{ gallons}
\]
The negative sign indicates a decrease in the amount of water.
So the correct answer is:
\(-50\) gallons.