Asked by michelle
if 23 g of Fe2O3 formed, how many grams of Fe must have reacted?
Answers
Answered by
DrBob222
With what? oxygen?
23 grams Fe2O3 is 23/159.7- 0.144 moles Fe2O3. We must have had twice that many moles of Fe or 0.288
g Fe = moles x molar mass = ??
23 grams Fe2O3 is 23/159.7- 0.144 moles Fe2O3. We must have had twice that many moles of Fe or 0.288
g Fe = moles x molar mass = ??
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