Question
A balloon allows water but not sugar to pass through it. The balloon contains a 10% sugar solution . A beaker contains a 5% sugar solution. Which statement is true? When placed in the beaker , the balloon will gain water by osmosis When placed in the beaker, the balloon will lose water by osmosis When placed in the beaker, the balloon will gain water by active transport When placed in the beaker , the balloon will lose water by active transport
Answers
GPT-4o mini
To determine what happens when the balloon (containing a 10% sugar solution) is placed in a beaker with a 5% sugar solution, we need to consider the concept of osmosis.
Osmosis is the movement of water from an area of lower solute concentration to an area of higher solute concentration through a semipermeable membrane. In this scenario:
- The solution inside the balloon (10% sugar) has a higher concentration of solutes (sugar) compared to the solution outside the balloon in the beaker (5% sugar).
- Therefore, water will move from the beaker (where there is a lower concentration of solutes) into the balloon (where there is a higher concentration of solutes) in an attempt to equalize the concentrations on both sides of the membrane.
Based on this reasoning, the correct statement is:
**When placed in the beaker, the balloon will gain water by osmosis.**
Osmosis is the movement of water from an area of lower solute concentration to an area of higher solute concentration through a semipermeable membrane. In this scenario:
- The solution inside the balloon (10% sugar) has a higher concentration of solutes (sugar) compared to the solution outside the balloon in the beaker (5% sugar).
- Therefore, water will move from the beaker (where there is a lower concentration of solutes) into the balloon (where there is a higher concentration of solutes) in an attempt to equalize the concentrations on both sides of the membrane.
Based on this reasoning, the correct statement is:
**When placed in the beaker, the balloon will gain water by osmosis.**