y^-9*y^-3*y^-5=

1 answer

To simplify the expression \( y^{-9} \cdot y^{-3} \cdot y^{-5} \), you can use the property of exponents that states when you multiply like bases, you add the exponents:

\[ y^a \cdot y^b = y^{a+b} \]

In this case, you add the exponents \(-9\), \(-3\), and \(-5\):

\[ -9 + (-3) + (-5) = -9 - 3 - 5 = -17 \]

So, the expression simplifies to:

\[ y^{-17} \]

If you want to express this with a positive exponent, you can write it as:

\[ \frac{1}{y^{17}} \]

Therefore, the final simplified form of the expression is:

\[ y^{-9} \cdot y^{-3} \cdot y^{-5} = y^{-17} = \frac{1}{y^{17}} \]