Yes, I am sure. Let's break it down step-by-step to confirm:
-
We want to determine how many times less \(10^2\) is than \(10^6\).
-
We calculate the ratio:
\[
\frac{10^2}{10^6}
\]
-
Using the exponent rule, where \(\frac{a^m}{a^n} = a^{m-n}\), we simplify this:
\[
\frac{10^2}{10^6} = 10^{2-6} = 10^{-4}
\]
This tells us that \(10^2\) is \(10^{-4}\) times \(10^6\), which means it is much smaller.
- To express it clearly: \(10^2\) is \(1/10^4\) of \(10^6\), which confirms that it's \(10^{-4}\) times \(10^6\).
Therefore, the correct expression of how many times less \(10^2\) is than \(10^6\) is indeed:
\[
10^{-4}
\]
If you have any further questions or need clarifications, feel free to ask!