Two weeks before an examination day, a librarian monitored the number of students who visited the library. Then they compared it with the number of visits made in an average week. Approximately 2×10^3

visits were reflected in their logbook during this two-week period, while only about 5×10^2
were reflected on an average week. How many times higher is the number of library visits before examination day compared to the library visits in an average week? Your answer should be a whole number.(1 point)
times

1 answer

To find out how many times higher the number of library visits before examination day is compared to the average weekly visits, we first need to understand the figures given:

  • Total visits in two weeks: \(2 \times 10^3 = 2000\)
  • Average visits in one week: \(5 \times 10^2 = 500\)

Now, since the librarian monitored the number of visits over a two-week period, we can compute the average visits per week for that period:

\[ \text{Average visits per week during two weeks} = \frac{2000 \text{ visits}}{2 \text{ weeks}} = 1000 \text{ visits/week} \]

Now, we need to compare this with the average visits:

  • Average visits in an average week: \(500\)

Next, we find how many times higher the visits were during the two-week period compared to the average visits in one week:

\[ \text{Number of times higher} = \frac{\text{Average visits during two weeks}}{\text{Average visits in one week}} = \frac{1000}{500} = 2 \]

So, the number of library visits before examination day is 2 times higher compared to the library visits in an average week.

Thus, the answer is:

2 times.