Apply the Properties of Integer Exponents to generate an equivalent expression to (5−3)6⋅ 51710−2%0D%0A(%0D%0A5%0D%0A−%0D%0A3%0D%0A)%0D%0A6%0D%0A⋅%0D%0A %0D%0A5%0D%0A17%0D%0A10%0D%0A−%0D%0A2%0D%0A with only positive exponents, then solve the expression. %0D%0A%0D%0AShow your work.%0D%0A%0D%0A(1 point)%0D%0A(5−3)6⋅ 51710−2=%0D%0A(%0D%0A5%0D%0A−%0D%0A3%0D%0A)%0D%0A6%0D%0A⋅%0D%0A %0D%0A5%0D%0A17%0D%0A10%0D%0A−%0D%0A2%0D%0A=%0D%0A

1 answer

To simplify the expression \((5^{-3})^6 \cdot 5^{1710^{-2}}\) and express it with only positive exponents, we will apply the properties of exponents step by step.

  1. Simplify \((5^{-3})^6\): \[ (5^{-3})^6 = 5^{-3 \cdot 6} = 5^{-18} \]

  2. Simplify \(5^{1710^{-2}}\): First, we interpret \(1710^{-2}\). \[ 1710^{-2} = \frac{1}{1710^2} \] Thus, \[ 5^{1710^{-2}} = 5^{\frac{1}{1710^2}} \text{ (We will leave it as is for now).} \]

Now we have: \[ 5^{-18} \cdot 5^{1710^{-2}} \]

  1. Combine the two expressions using the property of exponents that states \(a^m \cdot a^n = a^{m+n}\): \[ 5^{-18 + \frac{1}{1710^2}} \]

Now, we want to express this with only positive exponents. We can express \(5^{-18}\) as: \[ \frac{1}{5^{18}} \]

Thus, we rewrite the entire expression: \[ 5^{-18 + \frac{1}{1710^2}} = \frac{1}{5^{18 - \frac{1}{1710^2}}} \]

  1. Final expression with only positive exponents: \[ \frac{1}{5^{18 - \frac{1}{1710^2}}} \]

  2. Solving the expression: To find the exact numerical value, we can estimate \(1710^{-2}\): \[ 1710^2 = 2924100 \implies \frac{1}{1710^2} \approx 0 \]

Thus, \[ \text{For practical calculations: } 18 - \frac{1}{1710^2} \approx 18 \]

Hence, we get: \[ \frac{1}{5^{18}} \]

This is our final answer.

Summary

The equivalent expression with only positive exponents is: \[ \frac{1}{5^{18 - \frac{1}{1710^2}}} \] And numerically simplified (as much as needed) it approximates to: \[ \frac{1}{5^{18}} \]