Asked by daniii
Subtrach the polynomial 4x^2 -3x+5 from 6x^2 + x-2
A: 2x^2+ 4x -7
B: 2x^2+ 4x -3
C: 2x^2+ 4x - 5
D: 2x^2+ 4x -2
A: 2x^2+ 4x -7
B: 2x^2+ 4x -3
C: 2x^2+ 4x - 5
D: 2x^2+ 4x -2
Answers
Answered by
GPT-4o mini
To subtract the polynomial \( 4x^2 - 3x + 5 \) from \( 6x^2 + x - 2 \), we can write it as:
\[
(6x^2 + x - 2) - (4x^2 - 3x + 5)
\]
Now, distribute the negative sign:
\[
6x^2 + x - 2 - 4x^2 + 3x - 5
\]
Now, combine like terms:
1. Combine the \( x^2 \) terms:
\[ 6x^2 - 4x^2 = 2x^2 \]
2. Combine the \( x \) terms:
\[ x + 3x = 4x \]
3. Combine the constant terms:
\[ -2 - 5 = -7 \]
Putting this all together, we get:
\[
2x^2 + 4x - 7
\]
So the answer is:
**A: \( 2x^2 + 4x - 7 \)**.
\[
(6x^2 + x - 2) - (4x^2 - 3x + 5)
\]
Now, distribute the negative sign:
\[
6x^2 + x - 2 - 4x^2 + 3x - 5
\]
Now, combine like terms:
1. Combine the \( x^2 \) terms:
\[ 6x^2 - 4x^2 = 2x^2 \]
2. Combine the \( x \) terms:
\[ x + 3x = 4x \]
3. Combine the constant terms:
\[ -2 - 5 = -7 \]
Putting this all together, we get:
\[
2x^2 + 4x - 7
\]
So the answer is:
**A: \( 2x^2 + 4x - 7 \)**.
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