Question

according to the punnett square, what are the probabilities of each resulting genotype/phenotype when 2 hetorozygous pea plants are crossed. Match the probabitlity of the resulting phenotype to the genotype.
25% Tall offspring______
50% tall offspring______
25% short offspring_____


Tt
TT
tt

Answer 1

When two heterozygous pea plants (Tt) are crossed, we can set up a Punnett square to determine the probabilities of the resulting genotypes and phenotypes. Here is how the genotype distribution breaks down:

1. **Genotypes** from the cross Tt x Tt are:
- TT (Homozygous Tall): 1 out of 4
- Tt (Heterozygous Tall): 2 out of 4
- tt (Homozygous Short): 1 out of 4

This translates into probabilities:
- **TT**: 1/4 = 25%
- **Tt**: 2/4 = 50%
- **tt**: 1/4 = 25%

For phenotypes, since both TT and Tt plants are tall, the probabilities are as follows:
- **Tall offspring** (TT + Tt): 3 out of 4 = 75%
- **Short offspring** (tt): 1 out of 4 = 25%

Now, to match the probabilities of the resulting phenotype to the genotype:
- **25% Tall offspring:** TT
- **50% Tall offspring:** Tt
- **25% Short offspring:** tt

So in summary:
- 25% Tall offspring → TT
- 50% Tall offspring → Tt
- 25% Short offspring → tt