Given the quadratic equation (2x−7)(x+9)

check the solution in the following table by substitution and evaluating

(1 point)
Value Substituted Evaluate: Step 1 Step 2: True or False Statement?
(2x−7)(x+9)=0
original question
0 (2(0)−7)((0+9)=0
(−7)(9)=0
−63=0
false
3
-9
9


pa

1 answer

To check the solutions of the quadratic equation \((2x - 7)(x + 9) = 0\) using the table structure you provided, let's substitute the values into the equation and evaluate each step to see if we get a true statement.

Given Values to Check

  1. Value = 0

    • Substitute: \((2(0) - 7)((0 + 9)) = 0\)
    • Step 1: \((-7)(9) = 0\)
    • Step 2: \(-63 = 0\)
    • True or False Statement? False
  2. Value = 3

    • Substitute: \((2(3) - 7)((3 + 9)) = 0\)
    • Step 1: \((6 - 7)(12) = 0\)
    • Step 2: \((-1)(12) = 0\)
    • True or False Statement? False
  3. Value = -9

    • Substitute: \((2(-9) - 7)((-9 + 9)) = 0\)
    • Step 1: \((-18 - 7)(0) = 0\)
    • Step 2: \((-25)(0) = 0\)
    • True or False Statement? True (since any number multiplied by 0 is 0)
  4. Value = 9

    • Substitute: \((2(9) - 7)((9 + 9)) = 0\)
    • Step 1: \((18 - 7)(18) = 0\)
    • Step 2: \((11)(18) = 0\)
    • True or False Statement? False

Summary Table

| Value | Substituted | Evaluate: Step 1 | Step 2 | True or False Statement? | |-------|----------------------------------------|-----------------------|------------|--------------------------| | 0 | \((2(0)−7)((0+9))\) | \((-7)(9) = 0\) | \(-63 = 0\) | False | | 3 | \((2(3)−7)((3+9))\) | \((-1)(12) = 0\) | \(-12 = 0\) | False | | -9 | \((2(-9)−7)((-9+9))\) | \((-25)(0) = 0\) | \(-0 = 0\) | True | | 9 | \((2(9)−7)((9+9))\) | \((11)(18) = 0\) | \(198 = 0\) | False |

Final Comments

  • The only value that satisfies the equation \((2x - 7)(x + 9) = 0\) is \(x = -9\). The solutions to the original quadratic equation can also be found by setting each factor to zero:
    • \(2x - 7 = 0 \Rightarrow x = \frac{7}{2}\)
    • \(x + 9 = 0 \Rightarrow x = -9\)

So the complete solution set is \(\left{-9, \frac{7}{2}\right}\).

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