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Claudia's family is buying a new cabinet for their home. The height of the cabinet is 5 ft., its length is 4 ft., and its volum...Asked by Water
Claudia’s family is buying a new cabinet for their home. The height of the cabinet is 5 ft., its length is 4 ft., and its volume is 60 ft.3 . They need to know the width of the cabinet to make sure that it will fit in the space where they want to put it. Using the volume formula, V=lwh , rearrange the formula to highlight the quantity of interest. Note that volume is represented with a capital V in the formula.(1 point) w = ?/?
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Answered by
Water
No bot, Claudia’s family is buying a new cabinet for their home. The height of the cabinet is 5 ft., its length is 4 ft., and its volume is 60 ft.3 . They need to know the width of the cabinet to make sure that it will fit in the space where they want to put it. Using the volume formula, V=lwh , rearrange the formula to highlight the quantity of interest. Note that volume is represented with a capital V in the formula. What is the answer in fraction form?
Answered by
GPT-4o mini
To find the width (w) of the cabinet using the volume formula \( V = lwh \), we can rearrange the formula to solve for width.
Starting with the equation:
\[ V = lwh \]
We can solve for \( w \) by dividing both sides of the equation by \( lh \):
\[ w = \frac{V}{lh} \]
So the rearranged formula highlighting the quantity of interest (width) is:
\[ w = \frac{V}{lh} \]
Starting with the equation:
\[ V = lwh \]
We can solve for \( w \) by dividing both sides of the equation by \( lh \):
\[ w = \frac{V}{lh} \]
So the rearranged formula highlighting the quantity of interest (width) is:
\[ w = \frac{V}{lh} \]
Answered by
GPT-4o mini
To find the width \( w \) using the volume formula \( V = lwh \), where:
- \( V \) = volume
- \( l \) = length
- \( h \) = height
We need to rearrange the formula to solve for \( w \):
1. Start with the original formula:
\[
V = lwh
\]
2. Rearrange the formula to isolate \( w \):
\[
w = \frac{V}{lh}
\]
Given the values:
- \( V = 60 \, \text{ft}^3 \)
- \( l = 4 \, \text{ft} \)
- \( h = 5 \, \text{ft} \)
Substituting these values into the rearranged formula:
\[
w = \frac{60}{4 \cdot 5}
\]
Calculating the denominator:
\[
4 \cdot 5 = 20
\]
Now substitute back:
\[
w = \frac{60}{20}
\]
This simplifies to:
\[
w = 3
\]
So the width of the cabinet is \( 3 \, \text{ft} \).
In fraction form, the width can also be expressed as:
\[
w = \frac{3}{1}
\]
- \( V \) = volume
- \( l \) = length
- \( h \) = height
We need to rearrange the formula to solve for \( w \):
1. Start with the original formula:
\[
V = lwh
\]
2. Rearrange the formula to isolate \( w \):
\[
w = \frac{V}{lh}
\]
Given the values:
- \( V = 60 \, \text{ft}^3 \)
- \( l = 4 \, \text{ft} \)
- \( h = 5 \, \text{ft} \)
Substituting these values into the rearranged formula:
\[
w = \frac{60}{4 \cdot 5}
\]
Calculating the denominator:
\[
4 \cdot 5 = 20
\]
Now substitute back:
\[
w = \frac{60}{20}
\]
This simplifies to:
\[
w = 3
\]
So the width of the cabinet is \( 3 \, \text{ft} \).
In fraction form, the width can also be expressed as:
\[
w = \frac{3}{1}
\]