Question

simplify (6y+3y^3+2y^2)-(y^2-2y^3-3y)

Answer 1

Is this true or false?
8(6-2)=30

Answer 2

To simplify the expression \((6y + 3y^3 + 2y^2) - (y^2 - 2y^3 - 3y)\), follow these steps:

1. Distribute the negative sign across the second set of parentheses:
\[
6y + 3y^3 + 2y^2 - y^2 + 2y^3 + 3y
\]

2. Combine like terms:
- Combine the \(y^3\) terms:
\[
3y^3 + 2y^3 = 5y^3
\]
- Combine the \(y^2\) terms:
\[
2y^2 - y^2 = y^2
\]
- Combine the \(y\) terms:
\[
6y + 3y = 9y
\]

3. Write the combined expression:
\[
5y^3 + y^2 + 9y
\]

Thus, the simplified expression is:
\[
\boxed{5y^3 + y^2 + 9y}
\]

Answer 3

To determine if the statement \( 8(6-2) = 30 \) is true or false, we first need to evaluate the left side of the equation.

1. Calculate the expression inside the parentheses:
\[
6 - 2 = 4
\]

2. Now multiply by 8:
\[
8(4) = 32
\]

Now we can compare the result with the right side of the equation:
\[
32 \neq 30
\]

Thus, the statement \( 8(6-2) = 30 \) is **false**.