Question

The table shows the yearly rain totals in inches for the rainiest and driest cities in the United States. City 2010 2011 2012 2013 2014 2015 Seattle, WA 45.79 32.46 55.14 40.30 23.78 49.42 Las Vegas, NV 3.72 5.62 4.11 8.79 2.33 3.84 What is the difference between the median yearly rainfall for Seattle and Las Vegas? (1 point) Responses 36.58 in. 36.58 in. 39.07 in. 39.07 in. 41.68 in. 41.68 in. 43.045 in.

Answer 1

To find the median yearly rainfall for Seattle and Las Vegas, we first need to list each city's rainfall totals and then determine the median.

Seattle, WA Rainfall Totals:

• 2010: 45.79
• 2011: 32.46
• 2012: 55.14
• 2013: 40.30
• 2014: 23.78
• 2015: 49.42

Arranging these in order:

• 23.78
• 32.46
• 40.30
• 45.79
• 49.42
• 55.14

Since there are six values (an even number), the median is the average of the two middle numbers: Median = (40.30 + 45.79) / 2 = 43.045 in.

Las Vegas, NV Rainfall Totals:

• 2010: 3.72
• 2011: 5.62
• 2012: 4.11
• 2013: 8.79
• 2014: 2.33
• 2015: 3.84

Arranging these in order:

• 2.33
• 3.72
• 3.84
• 4.11
• 5.62
• 8.79

Again, since there are six values (an even number), the median is the average of the two middle numbers: Median = (3.84 + 4.11) / 2 = 3.975 in.

Now, calculate the difference between the median rainfall amounts: Difference = Median Seattle - Median Las Vegas Difference = 43.045 in. - 3.975 in. Difference = 39.07 in.

Therefore, the difference between the median yearly rainfall for Seattle and Las Vegas is 39.07 inches.